document.write( "Question 1034960: Sandy made a trip to a city 200 miles away and then returned home. Her average speed on the return trip was 10 mph less than her average speed going. If her total travel time was 9 hours, what was her average rate in each direction? \n" ); document.write( "

Algebra.Com's Answer #649624 by addingup(3677) $\"\"$ $\"About$

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200 out
\n" ); document.write( "200 back
\n" ); document.write( "9 hrs total
\n" ); document.write( "d= st
\n" ); document.write( "d/s = t
\n" ); document.write( " $\"200%2Fx%2B200%2F%28x-10%29+=+9\"$
\n" ); document.write( " $\"400%28x-5%29%2Fx%28x-10%29+=+9\"$
\n" ); document.write( " $\"400%28x-5%29+=+9x%28x-10%29\"$
\n" ); document.write( " $\"400x-2000+=+9x%28x-10%29\"$
\n" ); document.write( " $\"400x-2000+=+9x%5E2-90\"$
\n" ); document.write( " $\"9x%5E2%2B490x-2000+=+0%0D%0A%7B%7B%7B-%28%28x-50%29%289x-40%29%29=+0\"$
\n" ); document.write( "Multiply times -1
\n" ); document.write( " $\"%28x-50%29%289x-40%29=+0\"$
\n" ); document.write( " $\"x-50+=+0\"$ or $\"9x-40+=+0\"$
\n" ); document.write( " $\"x+=+50\"$ or $\"9x+=+40\"$ ; $\"x+=+40%2F9\"$
\n" ); document.write( "So, on the way out her speed was 50mph and on the return 50-10=40
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\n" ); document.write( "Check:
\n" ); document.write( "50+40 = 90; 90/2 = 45; 45*9 = 405 it should be 400, the 5 is the result of rounding numbers. So the answer is correct. \n" ); document.write( "

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