document.write( "Question 1034960: Sandy made a trip to a city 200 miles away and then returned home. Her average speed on the return trip was 10 mph less than her average speed going. If her total travel time was 9 hours, what was her average rate in each direction? \n" ); document.write( "
Algebra.Com's Answer #649621 by Alan3354(69443) You can put this solution on YOUR website! Sandy made a trip to a city 200 miles away and then returned home. Her average speed on the return trip was 10 mph less than her average speed going. If her total travel time was 9 hours, what was her average rate in each direction? \n" ); document.write( "------------- \n" ); document.write( "r = speed going \n" ); document.write( "--- \n" ); document.write( "d = r*t \n" ); document.write( "t = d/r \n" ); document.write( "200/r + 200/(r-10) = 9 \n" ); document.write( "200(r-10) + 200r = 9r(r-10) \n" ); document.write( "400r - 2000 = 9r^2 - 90r \n" ); document.write( "9r^2 - 490r + 1910 = 0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "================== \n" ); document.write( "r = 50.22 going, 40.22 returning \n" ); document.write( "---- \n" ); document.write( "Ignore the 4... solution, subtracting 10 would give a negative speed. \n" ); document.write( " |