document.write( "Question 1034821: Nicole invested a certain amount of money for one year and earned $78 in interest. Jon invested $260 more at an interest rate that was 1% less than Nicole, but earned the same amount of interest. Find Nicole's principal and interest rate. \r
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document.write( "please explain. \n" );
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Algebra.Com's Answer #649583 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Nicole invested a certain amount of money for one year and earned $78 in interest. Jon invested $260 more at an interest rate that was 1% less than Nicole, but earned the same amount of interest. Find Nicole's principal and interest rate. \n" ); document.write( ": \n" ); document.write( "let n = amt invested by N \n" ); document.write( "J invested $260 more, therefore \n" ); document.write( "(n+260) = amt invested by J \n" ); document.write( ": \n" ); document.write( "then \n" ); document.write( " \n" ); document.write( "J interest rate was 1% less, therefore \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "j's interest rate * j's amt = 78 \n" ); document.write( "( \n" ); document.write( "FOIL \n" ); document.write( "78 + \n" ); document.write( "subtract 78 from both sides \n" ); document.write( " \n" ); document.write( "multiply by n, form quadratic equation \n" ); document.write( "20280 - .01n^2 - 2.6n = 0 \n" ); document.write( "Multiply by -100 \n" ); document.write( "n^2 + 260n - 2028000 = 0 \n" ); document.write( "you can use the quadratic formula but this will factor \n" ); document.write( "(n+1560)(n-1300) = 0 \n" ); document.write( "the positive solution \n" ); document.write( "n = $1300 is N's investment \n" ); document.write( "Find the interest rate \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this by finding J's amt and int \n" ); document.write( "1300 + 260 = $1560 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |