document.write( "Question 1034930: X is 5 years older than y. Z is 6 years older than x. How old are each person if the sum of their aget is 31? \n" ); document.write( "
Algebra.Com's Answer #649575 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
X is 5 years older than Y.
X = Y+5
Z is 6 years older than X.
Z = X+6
...the sum of their ages is 31...
X+Y+Z = 31\r\n" );
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document.write( "First substitute (Y+5) for X in Z = X+6\r\n" );
document.write( "and simplify.\r\n" );
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document.write( "Then substitute (Y+5) for X and Z = (what you got)\r\n" );
document.write( "into X+Y+Z = 31 and solve for Y.\r\n" );
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document.write( "Then substitute that value for Y in X = Y+5 to\r\n" );
document.write( "find X.\r\n" );
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document.write( "Then substitute what you got for X in Z = X+6\r\n" );
document.write( "to find Z.\r\n" );
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document.write( "I won't tell you the answers but one of them is\r\n" );
document.write( "twice as old as another of them.\r\n" );
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document.write( "Edwin
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