document.write( "Question 1034911: A broker has invested $21,500 in two mutual funds, one earning 9% annual interest and the other earning 14%. After 1 year, his combined interest is $2,860. How much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #649549 by addingup(3677)![]() ![]() You can put this solution on YOUR website! Let the amount at 9% be x. \n" ); document.write( "0.09*x+0.14(21,500-x) = 2860 \n" ); document.write( "0.09x+3010-0.14x = 2860 \n" ); document.write( "-0.05x = -150 \n" ); document.write( "x = 3,000 this is the amount invested at 9% and: \n" ); document.write( "21,500-3000 = 18,500 is invested at 14% \n" ); document.write( "`````````````````````````````````````````````` \n" ); document.write( "Check: \n" ); document.write( "0.09*3000 = 270 \n" ); document.write( "0.14*18,500= 2,590 \n" ); document.write( "270+2,590 = 2,860 Correct \n" ); document.write( " |