document.write( "Question 1034868: explain why x=4 is not in the domain of the function f(x)= square root x-5? \n" ); document.write( "
Algebra.Com's Answer #649526 by harpazo(655)\"\" \"About 
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If you replace x with 4 in the given function the answer becomes root(-1).\r
\n" ); document.write( "\n" ); document.write( "The root of negative numbers does not exist in the real number system.\r
\n" ); document.write( "\n" ); document.write( "This is why x cannot be 4. The value of x = 4 stands outside the domain of the \r
\n" ); document.write( "\n" ); document.write( "function. \r
\n" ); document.write( "\n" ); document.write( "Prove:\r
\n" ); document.write( "\n" ); document.write( "f(x) = root(x - 5)\r
\n" ); document.write( "\n" ); document.write( "f(4) = root(4 - 5)\r
\n" ); document.write( "\n" ); document.write( "f(4) = root(-1)\r
\n" ); document.write( "\n" ); document.write( "So, x = 4 is undefined for this function.
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