document.write( "Question 1034838: Four years ago, Danielle was (2/3) as old as Jim was. Now she is (3/4) as old as he is. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #649498 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Call their ages NOW, d and j. Then we can write \n" ); document.write( "d - 4 = (2/3)(j - 4) and \n" ); document.write( "d = (3/4)j \n" ); document.write( "Now substitute that into the first equation and get \n" ); document.write( "(3/4)j - 4 = (2/3)(j-4) \n" ); document.write( "Multiply everything by 12 to clear fractions...we get \n" ); document.write( "9j - 48 = 8(j - 4) \n" ); document.write( "9j - 48 = 8j - 32 \n" ); document.write( "and \n" ); document.write( "j = 16 which means \n" ); document.write( "d = 12 \n" ); document.write( " |