document.write( "Question 89248: divide: p^2+4p-5/p^2+7p+10 × p+4/p-1
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Algebra.Com's Answer #64948 by malakumar_kos@yahoo.com(315)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( " divide: p^2+4p-5/p^2+7p+10 × p+4/p-1\r
\n" ); document.write( "\n" ); document.write( " Factorise p^2+4p-5 = p^2+5p-p-5 = p(p+5)-1(p+5) = (p+5).(p-1)
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\n" ); document.write( " p^2+7p+10 = p^2+5p+2p+10 = p(p+5)+2(p+5) = (p+5).(p+2)\r
\n" ); document.write( "\n" ); document.write( " Therefore p^2+4p-5/p^2+7p+10 x p+4/p-1 = (p+5).(p-1).(p+4)/(p+5).(p+2).(p-1)
\n" ); document.write( " = (p+4)/(p+2)
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