document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034799>Question 1034799</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me with this problem:<BR>\n" );
document.write( "Your family has decided to put a regular patio in your backyard similar to the shape of your backyard. Your backyard has a length of 40 feet and a width of 32 feet. The length of your new patio is 14 feet. Find the perimeter of your new patio.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #649478 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=649478\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We can use proportions to find the width of the patio...from that we can get the perimeter of it...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=40%2F32+=+14%2Fw ALIGN=MIDDLE  ALT=\"40%2F32+=+14%2Fw\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "40w = 32*14<BR>\n" );
document.write( "40w = 448<BR>\n" );
document.write( "w = 448/40 = 11.2 feet<BR>\n" );
document.write( "so that<BR>\n" );
document.write( "P = 2L + 2W = 2(14) + 2(11.2) = 28 + 22.4 = 50.4 feet </SPAN>\n" );
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