document.write( "Question 89305:
\n" ); document.write( "Problem 1. D= C-S/N (for S)\r
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\n" ); document.write( "\n" ); document.write( "Problem 2. A=1/2h(B+b)(for b)
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Algebra.Com's Answer #64939 by malakumar_kos@yahoo.com(315)\"\" \"About 
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\n" ); document.write( " Problem 1. D= C-S/N (for S)\r
\n" ); document.write( "\n" ); document.write( "Problem 2. A=1/2h(B+b)(for b)\r
\n" ); document.write( "\n" ); document.write( " 1) D = C-S/N
\n" ); document.write( " -S/N = D-C
\n" ); document.write( " -S = N(D-C)\r
\n" ); document.write( "\n" ); document.write( " S = -N(D-C) = N(C-D)\r
\n" ); document.write( "\n" ); document.write( " S = N(C-D)\r
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\n" ); document.write( "\n" ); document.write( " 2)A = 1/2 h(B+b) \r
\n" ); document.write( "\n" ); document.write( " 2A = h(B+b)\r
\n" ); document.write( "\n" ); document.write( " 2A/h = B+b\r
\n" ); document.write( "\n" ); document.write( " 2A/h - B = b Therefore b = (2A/h)-B .
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