document.write( "Question 1034697: Mary Jo spends $1,860 to buy stock in two companies. She pays $15 a share to one of the companies and $26 a share to the other. If she ends up with a total of 80 shares, how many shares did she buy at $15 a share and how many did she buy at $26 a share?\r
\n" ); document.write( "\n" ); document.write( "She bought
\n" ); document.write( " shares at $15 and
\n" ); document.write( " shares at $26.
\n" ); document.write( "I am so confused!!!
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Algebra.Com's Answer #649370 by fractalier(6550)\"\" \"About 
You can put this solution on YOUR website!
Okay, let me help you...
\n" ); document.write( "Let's let x be the number of shares she bought at $15.
\n" ); document.write( "Then the number of shares she bought at $26 must be 80-x.
\n" ); document.write( "The setup then looks like this:
\n" ); document.write( "15x + 26(80-x) = 1860
\n" ); document.write( "Now solve for x...we get
\n" ); document.write( "15x + 2080 - 26x = 1860
\n" ); document.write( "-11x = -220
\n" ); document.write( "x = 20 shares at $15 so that
\n" ); document.write( "80-x = 60 shares at $26 each
\n" ); document.write( "Now, that wasn't so bad, was it?
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