document.write( "Question 1034697: Mary Jo spends $1,860 to buy stock in two companies. She pays $15 a share to one of the companies and $26 a share to the other. If she ends up with a total of 80 shares, how many shares did she buy at $15 a share and how many did she buy at $26 a share?\r
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document.write( "She bought
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document.write( " shares at $15 and
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document.write( " shares at $26.
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document.write( "I am so confused!!! \n" );
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Algebra.Com's Answer #649370 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Okay, let me help you... \n" ); document.write( "Let's let x be the number of shares she bought at $15. \n" ); document.write( "Then the number of shares she bought at $26 must be 80-x. \n" ); document.write( "The setup then looks like this: \n" ); document.write( "15x + 26(80-x) = 1860 \n" ); document.write( "Now solve for x...we get \n" ); document.write( "15x + 2080 - 26x = 1860 \n" ); document.write( "-11x = -220 \n" ); document.write( "x = 20 shares at $15 so that \n" ); document.write( "80-x = 60 shares at $26 each \n" ); document.write( "Now, that wasn't so bad, was it? \n" ); document.write( " |