document.write( "Question 1034683: Given that f(x)=x^2-3x and g(x)=x+10, find
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document.write( "f+g=
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document.write( "f-g=
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document.write( "f*g=
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document.write( "f/g= \n" );
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Algebra.Com's Answer #649359 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! For f(x)=x^2-3x and g(x)=x+10, \n" ); document.write( "f+g= x^2-3x + x+10 \n" ); document.write( "f-g= x^2-3x - (x+10) \n" ); document.write( "f*g= (x^2-3x)(x+10) \n" ); document.write( "f/g= (x^2-3x)/(x+10) \n" ); document.write( "I plugged them all in, now you finish... \n" ); document.write( " |