document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89359>Question 89359</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A garden area is 30 ft long and 20 ft wide. A path of uniform width<BR>\n" );
document.write( "is set around the edge. If the remaining garden area is 400 ft2, what is the width of the path?\r<BR>\n" );
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document.write( "Taken from Beginning Algebra 6th Edition Ch. 10 Pg.835 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64935 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64935\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let w equal the width of the path ... the dimensions of the remaining garden area are 30-2w long and 20-2w wide\r<BR>\n" );
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document.write( "(30-2w)(20-2w)=400 ... FOILing gives 600-100w+4w^2=400 ... dividing by 4 gives 150-25w+w^2=100 ... w^2-25w+50=0\r<BR>\n" );
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document.write( "quadratic formula gives <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=w=%2825+%2B-+sqrt%2825%5E2-4%2A1%2A50%29%29%2F%282%2A1%29=%2825+%2B-+5sqrt%2817%29%29%2F2 ALIGN=MIDDLE  ALT=\"w=%2825+%2B-+sqrt%2825%5E2-4%2A1%2A50%29%29%2F%282%2A1%29=%2825+%2B-+5sqrt%2817%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so w=2.19 (approximately) </SPAN>\n" );
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