document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034635>Question 1034635</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve\r<BR>\n" );
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document.write( "What number must be added to the numerator and subtracted from the denominator of 1/2 to produce a fraction equivalent to -8/7? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #649332 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=649332\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the number x...then we write<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2Bx%29%2F%282-x%29+=+-8%2F7 ALIGN=MIDDLE  ALT=\"%281%2Bx%29%2F%282-x%29+=+-8%2F7\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now cross-multiply and solve<BR>\n" );
document.write( "7(1+x) = -8(2-x)<BR>\n" );
document.write( "7 + 7x = -16 + 8x<BR>\n" );
document.write( "23 = x<BR>\n" );
document.write( " </SPAN>\n" );
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