document.write( "Question 1034674: what is the sum of the first 100 natural Numbers excluding the multiples if 4 \n" ); document.write( "
Algebra.Com's Answer #649330 by sachi(548)![]() ![]() You can put this solution on YOUR website! the sum first 100 natural Numbers i.e 1+2+3+.....+100 \n" ); document.write( "as per AP \n" ); document.write( "the first term=1=a \n" ); document.write( "the common diff =1-d \n" ); document.write( "no of terms = 100=n \n" ); document.write( "now the sum=n/2[2a+(n-1)*d)=100*101/2=5050 \n" ); document.write( "now the sum of multiples of 4=4+8+12+.....+100 \n" ); document.write( "the last term=100=l \n" ); document.write( "the first term=4=a \n" ); document.write( "the common diff =4-d \n" ); document.write( "no of terms=n \n" ); document.write( "then 100=a+(n-1)*d=4+(n-1)*4=4n \n" ); document.write( "so n=25\r \n" ); document.write( "\n" ); document.write( "now the sum of multiples of 4=4+8+12+.....+100=25/2(a+l)=25/2*(4+100)=1300 \n" ); document.write( "so the sum of the first 100 natural Numbers excluding the multiples if 4 \n" ); document.write( "=5050-1300=3750 \n" ); document.write( "ans \n" ); document.write( " |