document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034657>Question 1034657</A>: <I><SPAN STYLE=\"word-break: break-all;\"> using substituting method, solve 3x+3y=10 and 2x-y=2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #649287 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=649287\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x+3y=10<BR>\n" );
document.write( "2x-y=2 multiply all times 3 and add to equation above:<BR>\n" );
document.write( "3x+3y=10<BR>\n" );
document.write( "+<BR>\n" );
document.write( "6x-3y=6<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "9x = 16<BR>\n" );
document.write( "x = 16/9 = 1 7/9 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );