document.write( "Question 1034651: The area of a rectangular field is 2c³-c²+6 square units.
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Algebra.Com's Answer #649282 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
The area of a rectangular field is 2c³-c²+6 square units.
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document.write( "First let's do this simpler one:\r\n" );
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\n" ); document.write( "The area of a rectangular field is 5 square units.
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document.write( "A = LW\r\n" );
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document.write( "Substitute 5 for A and 3 for L:\r\n" );
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document.write( "5 = 3W\r\n" );
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document.write( "Divide both sides by 3\r\n" );
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document.write( "\"5%2F3\"\"%22%22=%22%22\"\"3W%2F3\"\r\n" );
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document.write( "\"5%2F3\"\"%22%22=%22%22\"\"cross%283%29W%2Fcross%283%29\"\r\n" );
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document.write( "  1\r\n" );
document.write( "3)5\r\n" );
document.write( "  3\r\n" );
document.write( "  2\r\n" );
document.write( "Answer: The width is \"1%262%2F3\" \r\n" );
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document.write( "Now let's do yours exactly the same way:\r\n" );
document.write( "

\n" ); document.write( "The area of a rectangular field is 2c³-c²+6 square units.
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document.write( "A = LW\r\n" );
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document.write( "Substitute 2c³-c²+6 for A and c-2 for L:\r\n" );
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document.write( "2c³-c²+6 = (c-2)W\r\n" );
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document.write( "Divide both sides by (c-2)\r\n" );
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document.write( "\"%282c%5E3-c%5E2%2B6%29%2F%28c-2%29\"\"%22%22=%22%22\"\"%28c-2%29W%2F%28c-2%29\"\r\n" );
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document.write( "\"%282c%5E3-c%5E2%2B6%29%2F%28c-2%29\"\"%22%22=%22%22\"\"cross%28c-2%29W%2Fcross%28c-2%29\"\r\n" );
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document.write( "         2c² + 3c + 6\r\n" );
document.write( "c-2)2c³ - c² + 0c + 6\r\n" );
document.write( "    2c³ -4c²\r\n" );
document.write( "         3c² + 0c\r\n" );
document.write( "         3c² - 6c\r\n" );
document.write( "               6c + 6\r\n" );
document.write( "               6c -12\r\n" );
document.write( "                   18\r\n" );
document.write( "  \r\n" );
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document.write( "Answer: The width is \"2c%5E2+%2B+3c+%2B+6+%2B+18%2F%28c-2%29\" \r\n" );
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document.write( "Edwin
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