document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034607>Question 1034607</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hoshi is working on an art project in the shape of a triangular prism. The sides of the triangle are 2.4 feet, 1.5 feet, and 1.3 feet. Find the measures of the angles of the triangle to the nearest tenth </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #649258 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=649258\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's use the Law of Cosines to find one angle, and use it again to find a second angle. The third angle is easy because the angles in EVERY triangle add up to 180 degrees.<BR>\n" );
document.write( "```````````````````````````````````````````````````````<BR>\n" );
document.write( "Let's call the sides: 2.4 a, 1.5 b, and 1.3 c. And the angles A, B, and C:<BR>\n" );
document.write( "cos(C) = (a^2+b^2&#8722;c^2)/2ab<BR>\n" );
document.write( "cos(C) = (2.4^2+1.5^2-1.3^2)/[2(2.4*1.5)] = 0.8778<BR>\n" );
document.write( "C = cos^-1(0.8778)= 28.62 degrees<BR>\n" );
document.write( "```````````````````````````````````````````````````<BR>\n" );
document.write( "Now you have angle C. Do the same for one other angle, then add the two angles and subtract the result from 180 to get your third angle.<BR>\n" );
document.write( "John </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );