document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034575>Question 1034575</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me solve the equation below. I'm suppose to covert it to standard form. I'm a little confuse though because I have tried dividing the equation by -3 as well as factoring, but I just can't seem to solve for what I need. Thank you.\r<BR>\n" );
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document.write( "3x^2+6x+y^2-6y=-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #649223 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=649223\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Can you please help me solve the equation below. I'm suppose to covert it to standard form. I'm a little confuse though because I have tried dividing the equation by -3 as well as factoring, but I just can't seem to solve for what I need. Thank you.\r<BR>\n" );
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document.write( "3x^2+6x+y^2-6y=-3<BR>\n" );
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document.write( "You have 1 equation in 2 variables, x & y.<BR>\n" );
document.write( "You can solve for x in terms of y, or vice versa.<BR>\n" );
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document.write( "If you graph it, you'll get an ellipse.  Each point on the ellipse satisfies the equation. </SPAN>\n" );
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