document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89356>Question 89356</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 9x+7=5x-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64922 by </B><A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><B>malakumar_kos@yahoo.com(315)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=malakumar_kos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64922\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "   9x+7=5x-3<BR>\n" );
document.write( "   SINCE WE HAVE TO find the value of x  let us bring  x terms to L.H.S\r<BR>\n" );
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document.write( "       9x+7 = 5x-3<BR>\n" );
document.write( "       9x+7-5x = 5x-3-5x     (subtract 5x  on both sides)<BR>\n" );
document.write( "           4x +7 = -3<BR>\n" );
document.write( "        4x+7-7 = -3-7        (subtract 7 on both sides)<BR>\n" );
document.write( "             4x = -10<BR>\n" );
document.write( "              x = -10/4<BR>\n" );
document.write( "                = -5/2 </SPAN>\n" );
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