document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89345>Question 89345</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me with this problem.\r<BR>\n" );
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document.write( "Find the solution sets for\r<BR>\n" );
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document.write( "(sqrt2x+1) - (sqrt x) = 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64921 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64921\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (sqrt2x+1) - (sqrt x) = 1<BR>\n" );
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document.write( "Square both sides to get:<BR>\n" );
document.write( "2x+1 -2sqrt(x(2x+1)) + x = 1<BR>\n" );
document.write( "Simplify and isolate the remaining radical, as follows:<BR>\n" );
document.write( "2sqrt(2x^2+x) =3x<BR>\n" );
document.write( "Square both sides to get:<BR>\n" );
document.write( "4(2x^2+x) = 9x^2<BR>\n" );
document.write( "8x^2+4x = 9x^2<BR>\n" );
document.write( "x^2-4x=0<BR>\n" );
document.write( "x(x-4)=0<BR>\n" );
document.write( "x=0 or x=4<BR>\n" );
document.write( "Check the answer in the original equation:(sqrt2x+1) - (sqrt x) = 1<BR>\n" );
document.write( "Does x=0? : sqrt(1)-sqrt(1)=1 : False<BR>\n" );
document.write( "Does x=4? ; sqrt(9)-sqrt(4) = 1 : True<BR>\n" );
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document.write( "Final Answer: x=4<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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