document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1028221>Question 1028221</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 8 feet longer than its wide. If each side is increased 8 feet, then the area is multiplied by 3. What was the size of the original rectangle? \r<BR>\n" );
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document.write( "The width or short side is<BR>\n" );
document.write( "The Length or the long side is  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #649196 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=649196\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let w=width of first rectangle, and a=area. Original length, l, is w+8;<BR>\n" );
document.write( "w(w+8)=a<BR>\n" );
document.write( "w^2+8w=a<BR>\n" );
document.write( "3w^2+24w=3a<BR>\n" );
document.write( "The second rectangle is;<BR>\n" );
document.write( "(w+8)(w+16)=3a<BR>\n" );
document.write( "w^2+24w+128=3w^2+24w<BR>\n" );
document.write( "2w^2=128<BR>\n" );
document.write( "w^2=64<BR>\n" );
document.write( "w=8<BR>\n" );
document.write( "The original rectangle was 8 ft in width; 16 feet length!!!!!!!!!! </SPAN>\n" );
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