document.write( "Question 89355: Factoring with a coefficient greater than 1\r
\n" ); document.write( "\n" ); document.write( "5yto the 2nd+7y-6
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Algebra.Com's Answer #64919 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
In order to factor \"5%2Ay%5E2%2B7%2Ay-6\", first multiply 5 and -6 to get -30 and we need to ask ourselves: What two numbers multiply to -30 and add to 7? Lets find out by listing all of the possible factors of -30\r
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\n" ); document.write( "\n" ); document.write( "Factors:\r
\n" ); document.write( "\n" ); document.write( "1,2,3,5,6,10,15,30,\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-5,-6,-10,-15,-30, List the negative factors as well. This will allow us to find all possible combinations\r
\n" ); document.write( "\n" ); document.write( "These factors pair up to multiply to -30.\r
\n" ); document.write( "\n" ); document.write( "(-1)*(30)=-30\r
\n" ); document.write( "\n" ); document.write( "(-2)*(15)=-30\r
\n" ); document.write( "\n" ); document.write( "(-3)*(10)=-30\r
\n" ); document.write( "\n" ); document.write( "(-5)*(6)=-30\r
\n" ); document.write( "\n" ); document.write( " Now which of these pairs add to 7? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 7\r
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First Number|Second Number|Sum
1|-30|1+(-30)=-29
2|-15|2+(-15)=-13
3|-10|3+(-10)=-7
5|-6|5+(-6)=-1
-1|30|(-1)+30=29
-2|15|(-2)+15=13
-3|10|(-3)+10=7
-5|6|(-5)+6=1
We can see from the table that -3 and 10 add to 7. So the two numbers that multiply to -30 and add to 7 are: -3 and 10\r
\n" ); document.write( "\n" ); document.write( " So the original quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"5%2Ay%5E2%2B7%2Ay-6\"\r
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\n" ); document.write( "\n" ); document.write( "breaks down to this (just replace \"7%2Ay\" with the two numbers that multiply to -30 and add to 7, which are: -3 and 10)\r
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\n" ); document.write( "\n" ); document.write( " \"5%2Ay%5E2-3y%2B10y-6\"\r
\n" ); document.write( "\n" ); document.write( "Group the first two terms together and the last two terms together like this:\r
\n" ); document.write( "\n" ); document.write( "\"%285%2Ay%5E2-3y%29%2B%2810y-6%29\"\r
\n" ); document.write( "\n" ); document.write( "Factor a y out of the first group and factor a 2 out of the second group.\r
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\n" ); document.write( "\n" ); document.write( "\"y%285y-3%29%2B2%285y-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now since we have a common term \"5y-3\" we can combine the two terms. \r
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\n" ); document.write( "\n" ); document.write( "\"%28y%2B2%29%285y-3%29\" Combine like terms. \r
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So the quadratic \"5%2Ay%5E2%2B7%2Ay-6\" factors to\r
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\n" ); document.write( "\n" ); document.write( "\"%28y%2B2%29%285y-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Notice how \"%28y%2B2%29%285y-3%29\" foils back to our original problem \"5%2Ay%5E2%2B7%2Ay-6\". This verifies our answer. \n" ); document.write( "
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