document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034486>Question 1034486</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three people are to share an amount of money in the following parts: 1/2, 1/3, and 1/6. Each person takes some money from this amount of money until there is nothing left. The first person then returns 1/2 of what he took. The second person then returns 1/3 of what he took, and the third person returns 1/6 of what he took. When the total of what was returned is divided equally among the three, each has his correct share, namely, 1/2, 1/3, and 1/6. How much money was in the original amount and how much did each person get from the original amount of money? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #649142 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=649142\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let guy A get 1/2 of the original amount, guy B get 1/3, and guy C get 1/6.\r<BR>\n" );
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document.write( "ANSWER:  The original amount would be 47 times of whatever guy C took initially.<BR>\n" );
document.write( "Guy B took 13 times as much as what guy C took initially, and guy A took 33 times as much as what guy C took initially. </SPAN>\n" );
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