document.write( "Question 89352: Hi Everyone, I was supposed to solve x^2+10=19....I came up with the solution of +(w/a line under it)3 Am I correct??? I would appreciate anyone reviewing this problem for me...Thanks \n" ); document.write( "
Algebra.Com's Answer #64913 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2%2B10=19\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B10-19=0\" Subtract 19 from both sides\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"x%5E2%2B10%2Ax-19=0\" ( notice \"a=1\", \"b=10\", and \"c=-19\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-10+%2B-+sqrt%28+%2810%29%5E2-4%2A1%2A-19+%29%29%2F%282%2A1%29\" Plug in a=1, b=10, and c=-19\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-10+%2B-+sqrt%28+100-4%2A1%2A-19+%29%29%2F%282%2A1%29\" Square 10 to get 100 \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-10+%2B-+sqrt%28+100%2B76+%29%29%2F%282%2A1%29\" Multiply \"-4%2A-19%2A1\" to get \"76\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-10+%2B-+sqrt%28+176+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-10+%2B-+4%2Asqrt%2811%29%29%2F%282%2A1%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-10+%2B-+4%2Asqrt%2811%29%29%2F2\" Multiply 2 and 1 to get 2\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-10+%2B+4%2Asqrt%2811%29%29%2F2\" or \"x+=+%28-10+-+4%2Asqrt%2811%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "which split up to\r
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\n" ); document.write( "\n" ); document.write( "\"x=-10%2F2%2B4%2Asqrt%2811%29%2F2\" or \"x=-10%2F2-4%2Asqrt%2811%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "and simplify to\r
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\n" ); document.write( "\n" ); document.write( "\"x=-5%2B2%2Asqrt%2811%29\" or \"x=-5-2%2Asqrt%2811%29\"\r
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\n" ); document.write( "\n" ); document.write( "Which approximate to\r
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\n" ); document.write( "\n" ); document.write( "\"x=1.6332495807108\" or \"x=-11.6332495807108\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=1.6332495807108\" or \"x=-11.6332495807108\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"x%5E2%2B10%2Ax-19\", we get:\r
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\n" ); document.write( "\n" ); document.write( "when we use the root finder feature on a calculator, we find that \"x=1.6332495807108\" and \"x=-11.6332495807108\".So this verifies our answer
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