document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034455>Question 1034455</A>: <I><SPAN STYLE=\"word-break: break-all;\"> g(t) = (t^2 + 2)/ (2t-7), find g'(t)   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #649114 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=649114\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the denominator is (2t-7)^2<BR>\n" );
document.write( "the numerator is (2t-7)(t^2)-(t^2+2)(2).  That is 2t^3-7t^2-2t^2-4<BR>\n" );
document.write( "{2t^3-9t^2-4)}/(2t-7)^2<BR>\n" );
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document.write( "This can be done with the product rule, but it may be more difficult<BR>\n" );
document.write( "write as (t^2+2)(2t=7)^(-1) </SPAN>\n" );
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