document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034410>Question 1034410</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve. Round to the nearest tenth of necessary\r<BR>\n" );
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document.write( "Donna and Evan canoed a total of 14 mi upstream and back. The round trip took 8 hrs. If they row at a rate of 4 mi/hr in still water, how fast was the current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #649111 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=649111\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's use r as our rate of the current; Assuming they canoed 14/2, or 7 miles each way, then:<BR>\n" );
document.write( "(7 miles/4+rmph)+(7 miles/4-rmph)=8<BR>\n" );
document.write( "7(4+r)+7(4-r)=8(16-r^2)<BR>\n" );
document.write( "28+7r+28-76=128-8r^2<BR>\n" );
document.write( "8r^2=72<BR>\n" );
document.write( "r^2=9<BR>\n" );
document.write( "r=3<BR>\n" );
document.write( "The rate of the river is 3 mph!!!!!!!!<BR>\n" );
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