document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=89349>Question 89349</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In 1975 the population of the Earth was approximately 4 billion and doubling every 35 years. The formula for the population P in year Y for this doubling rate is P(in billions)=4X2^[(y-1975)/35]<BR>\n" );
document.write( "What will the population of the US be in 2025 if this growth rate continues </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64911 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64911\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The formula for the population P in year Y for this doubling rate is<BR>\n" );
document.write( " P(in billions)=4X2^[(y-1975)/35]<BR>\n" );
document.write( "What will the population of the US be in 2025 if this growth rate continues<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "P = 4*2^[(2025-1975)/35]<BR>\n" );
document.write( "P = 4 * [2.6918000...]<BR>\n" );
document.write( "P = 10.76720... billion<BR>\n" );
document.write( "==============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );