document.write( "Question 1030135: Please help:
\n" ); document.write( "The length of a rectangular swimming pool is twice its width. The pool is surrounded by a walk that is 2 feet wide. The area of the region consisting of the pool and the walk is 1056 square feet.\r
\n" ); document.write( "\n" ); document.write( "(a) Use the method of completing the square to determine the dimensions of the swimming pool.\r
\n" ); document.write( "\n" ); document.write( "The length of the pool is ____ feet, and the width of the pool is ____feet.\r
\n" ); document.write( "\n" ); document.write( "(b) If the material for the walk costs $8 per square foot, how much would the material cost for the entire walk?\r
\n" ); document.write( "\n" ); document.write( "The material would cost $____ .
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Algebra.Com's Answer #649083 by jorel555(1290)\"\" \"About 
You can put this solution on YOUR website!
Say the width of your pool is w; the length is then equivalent to 2w. The width and length of your walkway are w+4 (2 feet are added to each side, thus adding 4 to the total), and 2w+4. Thus the area is:
\n" ); document.write( "(w+4)(2w+4)=1056
\n" ); document.write( "2w^2+12w+16=1056
\n" ); document.write( "2w^2+12w-1040=0
\n" ); document.write( "w^2+6w-520=0
\n" ); document.write( "(w+26)(w-20)=0
\n" ); document.write( "w=-26,20
\n" ); document.write( "Our only real solution is width=20, length=40!!!!!!!!
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