document.write( "Question 1033786: if $P are invested at an interest rate r compunded annually, at the end of 5 years the amount will be? A=P(1=r)^5\r
\n" ); document.write( "\n" ); document.write( "at what interest rate will $3000 increase to $5500 in 5 years? r=\r
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Algebra.Com's Answer #649065 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
\"A=P%281%2Br%29%5E5\" ==> \"5500+=+3000%281%2Br%29%5E5\"\r
\n" ); document.write( "\n" ); document.write( "==> \"11%2F6+=+%281%2Br%29%5E5\" ==> \"r+=+root%285%2C+11%2F6%29-1+=+0.12888\" to five significant figures.\r
\n" ); document.write( "\n" ); document.write( "Therefore, r = 12.9%.
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