document.write( "Question 1034411: solve. Round to the nearest tenth of necessary\r
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\n" ); document.write( "\n" ); document.write( "A certain computer can grade 2000 objective-answer exams in 10 sec. A new computer can grade the 2000 exams in less time. If the two computers together can grade 2000 exams in 3 sec, how long does it take the new computer alone to do the grading?
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Algebra.Com's Answer #649060 by robertb(5830)\"\" \"About 
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Let x be the number of seconds it takes for the new computer to grade the 2,000 exams. Then in 1 second, 1/x of the job is done.
\n" ); document.write( "The older computer grades the 2,000 exams in 10 seconds. Hence in one second 1/10 of the job is done.\r
\n" ); document.write( "\n" ); document.write( "The combined rate is \"1%2Fx+%2B+1%2F10\".\r
\n" ); document.write( "\n" ); document.write( "==> \"3%281%2Fx+%2B+1%2F10%29+=+1\" ==> \"3%2Fx+%2B+3%2F10+=+1\" ==> \"3%2Fx+=+7%2F10\" ==> x = 30/7, or \"x+=+4%262%2F7\" seconds.
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