document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1033770>Question 1033770</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a parallelogram  is 'p' sq. cm an its height is 'q' cm . A second parallelogram has equal area but its base is ‘r’ cm  more than that of the first. Obtain an expression in terms of p.q.r for the height ‘h’ of the second parallelogram  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #649044 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=649044\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the area of the first parallelogram is p and its height is q, then its base is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p%2Fq ALIGN=MIDDLE  ALT=\"p%2Fq\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  The second parallelogram has the same area p.  Its base then will be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p%2Fq+%2B+r ALIGN=MIDDLE  ALT=\"p%2Fq+%2B+r\"   DISABLED_style= \"max-width:90%; height:auto;\" >, by hypothesis.  Hence its height will be \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=p%2F%28+p%2Fq+%2B+r+++%29++=+%28pq%29%2F%28p%2Bqr%29 ALIGN=MIDDLE  ALT=\"p%2F%28+p%2Fq+%2B+r+++%29++=+%28pq%29%2F%28p%2Bqr%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > cm. </SPAN>\n" );
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