document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034377>Question 1034377</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the standard form of the equation of the circle that is tangent to the y-axis and has its center at (3, -2).\r<BR>\n" );
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document.write( "(x - 3)² + (y + 2)² = 9<BR>\n" );
document.write( "(x + 3)² + (y - 2)² = 9<BR>\n" );
document.write( "(x - 3)² + (y + 2)² = 4<BR>\n" );
document.write( "(x + 2)² + (y - 3)² = 4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #649013 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=649013\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given point is in Q4, and you can easily identify the distance from center (3,-2) to y-axis, being 3.  Just fit into the standard form from that.\r<BR>\n" );
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