document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008357>Question 1008357</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Concrete is made of cement, water, and aggregate (sand and gravel). Aggregate should make up 75% of the total mass of concrete. If you have a concrete mix that is 60%aggregate, how many kilograms of this mix and how many kilograms of aggregate should be combined to form 48 kilograms of the concrete mix with the proper percentage of aggregate?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #649010 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=649010\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assuming the aggregate is pure 100% aggregate, then let x be the amount of 60% aggregate you start with. Then:<BR>\n" );
document.write( ".6x+1(48-x)=48(.75)<BR>\n" );
document.write( ".6x+48-x=36<BR>\n" );
document.write( "12=.4x<BR>\n" );
document.write( "x=12/.4=30<BR>\n" );
document.write( "30 ks of 60% aggregate mixed with 18 ks of pure aggregate make 48 ks of 75% aggregate!!!!!!! </SPAN>\n" );
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