document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034327>Question 1034327</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 13 builders took 6 months to build a house how long will 10 builders take to build the house </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648949 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648949\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a problem in inverse variation, i.e., a relationship between two variables such that an increase in one causes a corresponding decrease in the other, or a decrease in one causes a corresponding increase in the other.  <BR>\n" );
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document.write( "n1/n2 = d2/d1=<BR>\n" );
document.write( "13/10 = x/6 Cross multiply:<BR>\n" );
document.write( "13*6 = 10*x<BR>\n" );
document.write( "78 = 10x<BR>\n" );
document.write( "x = 7.8 months<BR>\n" );
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document.write( "John </SPAN>\n" );
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