document.write( "Question 89338: solve by completing the square\r
\n" ); document.write( "\n" ); document.write( "x^2-6x-3=0 \n" ); document.write( "
Algebra.Com's Answer #64893 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
solve by completing the square\r
\n" ); document.write( "\n" ); document.write( "x^2-6x-3=0
\n" ); document.write( "---------
\n" ); document.write( "x^2-6x + (6/2)^2 = 3+(6/2)^2
\n" ); document.write( "x^2-6x+9 = 12
\n" ); document.write( "Factor the left side to get:\r
\n" ); document.write( "\n" ); document.write( "(x-3)^2 = 12
\n" ); document.write( "Take the square root of both sides to get:
\n" ); document.write( "(x-3) = 2sqrt3 or (x-3) = -2sqrt3\r
\n" ); document.write( "\n" ); document.write( "Solve for x:
\n" ); document.write( "x= 3+2sqrt3 or x= 3-2sqrt3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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