document.write( "Question 1034320: larry mitchell invested part of his $34,000 advance at 5% annual simple interest and the rest at 7% annual simple interest. the yearly total from both was $2,300. Find the amount at each rate. \n" ); document.write( "
Algebra.Com's Answer #648929 by fractalier(6550)\"\" \"About 
You can put this solution on YOUR website!
Call the amount invested at 5%, x.
\n" ); document.write( "Then the amount invested at 7% would be 34000-x.
\n" ); document.write( "The set up then looks like this...
\n" ); document.write( ".05x + .07(34000-x) = 2300
\n" ); document.write( "Now solve for x...
\n" ); document.write( ".05x + 2380 - .07x = 2300
\n" ); document.write( "-.02x = - 80
\n" ); document.write( "x = $4000 invested at 5% which means
\n" ); document.write( "34000-4000 = $30,000 invested at 7%
\n" ); document.write( "
\n" );