document.write( "Question 1034279: y=3+sqrt of 2
\n" ); document.write( "then sqrt of y=?
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Algebra.Com's Answer #648924 by Alan3354(69443) $\"\"$ $\"About$

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y=3+sqrt of 2
\n" ); document.write( "then sqrt of y=?
\n" ); document.write( "------------
\n" ); document.write( " $\"sqrt%28y%29+=+sqrt%283+%2B+sqrt%282%29%29\"$ \n" ); document.write( "

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