document.write( "Question 1034271: A collection of nickels, dimes, and quarters consist of 60 coins with a total of $6.50. If there are 3 times as many dimes as quarters, find the number of each type of coins. \n" ); document.write( "

Algebra.Com's Answer #648893 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "A collection of nickels, dimes, and quarters consist of 60 coins with a total of $6.50. If there are 3 times as many dimes as quarters, find the number of each type of coins.
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Let number of nickels and quarters, N, and Q, respectively
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document.write( "Then number of dimes = 3Q
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document.write( "We then get: N + Q + 3Q = 60_____N + 4Q = 60 ------- eq (i)
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document.write( "Also, .05N + .25Q + .1(3Q) = 6.5____.05N + .25Q + .3Q = 6.5____.05N + .55Q = 6.5 ---- eq (ii)
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document.write( "- .05N - .2Q = - 3 ------- Multiplying eq (i) by – .05 ------- eq (iii)
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document.write( ".35Q = 3.5 ------- Adding eqs (iii) & (ii)
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document.write( "Q, or number of quarters = , or 
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document.write( "N + 4(10) = 60 --------- Substituting 10 for Q in eq (i)
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document.write( "N + 40 = 60
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document.write( "N, or number of nickels = 60 – 40, or 
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document.write( "Number of dimes: 3(10), or  \n" );
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