document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034271>Question 1034271</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A collection of nickels, dimes, and quarters consist of 60 coins with a total of $6.50. If there are 3 times as many dimes as quarters, find the number of each type of coins. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648873 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648873\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n+d+q = 60<BR>\n" );
document.write( "d = 3q<BR>\n" );
document.write( "0.05n+0.10d+0.25q = 6.50<BR>\n" );
document.write( "0.05n+0.10(3q)+0.25q = 6.50<BR>\n" );
document.write( "0.05n+0.30q+0.25q = 6.50<BR>\n" );
document.write( "0.55q = 6.50-0.05n This is how far I can go with the information you provided </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );