document.write( "Question 1023608: Roger flew his aeroplane from Dawson City to Fort Mcpherson and back into the Yukon territories. In still air, his aeroplane flies 200 km per hour. There was a steady wind the whole time, which slowed his rate down on the way up, and speeded him up on the way back. The flight up took 3.75 hours. The flight back took 2.5 hours. What was the speed of the steady wind? \n" ); document.write( "
Algebra.Com's Answer #648848 by jorel555(1290)\"\" \"About 
You can put this solution on YOUR website!
Assuming the distant is constant;
\n" ); document.write( "3.75(200-x)=2.5(200+x)
\n" ); document.write( "750-3.75x=500+2.5x
\n" ); document.write( "250=6.25x
\n" ); document.write( "x=250/6.25=40 kph steady wind speed!!!!!!!!!
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