document.write( "Question 89307: Tutor could you help me please? My problem is: If 6a/2=12 then a= ????\r
\n" ); document.write( "\n" ); document.write( "Would the answer be 3?\r
\n" ); document.write( "\n" ); document.write( "Thank you for your help!
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Algebra.Com's Answer #64884 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
If \"6a%2F2=12\" then a= ???? \r
\n" ); document.write( "\n" ); document.write( "Lets look at the left side of the equation:\r
\n" ); document.write( "\n" ); document.write( "Now we know that \"6a%2F2=3a\". So now we have:\r
\n" ); document.write( "\n" ); document.write( "\"3a=12\" divide both sides by 3\r
\n" ); document.write( "\n" ); document.write( "\"3a%2F3=12%2F3\" or\r
\n" ); document.write( "\n" ); document.write( "\"a=4\"\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "\"6%2A4%2F2=12\"
\n" ); document.write( "\"24%2F2=12\"
\n" ); document.write( "\"12=12\"\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor
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