document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1021145>Question 1021145</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a girl paddles her kayak upstream from her home to her friends home taking 2 1/2 hours for the journey.she returns that afternoon in 1 1/2 hours. <BR>\n" );
document.write( "if the river is flowing at 2 1/2 km/h find: \r<BR>\n" );
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document.write( "A.her paddling speed in still water <BR>\n" );
document.write( "B.the distance to her friends place </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648833 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648833\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assuming the distances upstream and downstream are the same, then:<BR>\n" );
document.write( "2.5(x-2.5)kmh=1.5(x+2.5)kmh<BR>\n" );
document.write( "2.5x-6.25=1.5x+3.75<BR>\n" );
document.write( "1x=10 kmh in still water......<BR>\n" );
document.write( "1.5(10+2.5)=18.75 kilometers to her friend's house!!!!!! </SPAN>\n" );
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