document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1030809>Question 1030809</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rowing team rowed <BR>\n" );
document.write( "100<BR>\n" );
document.write( " miles while going with the current in the same amount of time as it took to row <BR>\n" );
document.write( "20<BR>\n" );
document.write( " miles going against the current. The rate of the current was <BR>\n" );
document.write( "6<BR>\n" );
document.write( " miles per hour. Find the rate of the rowing team in still water.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648829 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648829\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the time for the distances is the same, then:<BR>\n" );
document.write( "100/x+6=20/x-6<BR>\n" );
document.write( "100x-600=20x+120<BR>\n" );
document.write( "80x=720<BR>\n" );
document.write( "x=9 miles an hour as the rowing teams' rate in still water!!!!!!! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );