document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034134>Question 1034134</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Make a table and solve. Round to the nearest tenth of necessary\r<BR>\n" );
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document.write( "The first bus for the senior trip left the school 1/2 hr later than a second bus, which traveled at an average speed of 45 mi/hr. When it finally departed, the second bus averaged 50 million/hr. How long did it take second bus to catch up with the first bus? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648827 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648827\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assuming the first bus left 1/2 hour early, traveling at 45 mph, then it had a 45 x 1/2 hr=27.5 mile head start. So:<BR>\n" );
document.write( "50 mph X x hours = 45 mph X x hours + 27.5 miles<BR>\n" );
document.write( "50x=45x+27.5<BR>\n" );
document.write( "5x=27.5<BR>\n" );
document.write( "x=5.5<BR>\n" );
document.write( "The second bus caught up to the first after 5.5 hours of traveling.!!!!!!! </SPAN>\n" );
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