document.write( "Question 1034185: Plz solve- 3 men and 18 children together take 2 days
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Algebra.Com's Answer #648793 by ikleyn(52786)\"\" \"About 
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document.write( "Let m be the man's   rate of work, in terms of \"job%2Fday\", and\r\n" );
document.write( "let c be the child's rate of work, in the same terms.\r\n" );
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document.write( "Then from the condition you have this system of equations\r\n" );
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document.write( "3m + 18c = \"1%2F2\",   (1)\r\n" );
document.write( "6m       = \"1%2F3\".   (2)\r\n" );
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document.write( "From (2), m = \"1%2F%283%2A6%29\" = \"1%2F18\".\r\n" );
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document.write( "Substitute it into (1). You will get\r\n" );
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document.write( "\"3%2F18\" + 18c = \"1%2F2\"  --->  \"1%2F6\" + 18c = \"1%2F2\"  --->  18c = \"1%2F2+-+1%2F6\" = \"2%2F6\" = \"1%2F3\".\r\n" );
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document.write( "Hence,  c = \"1%2F%283%2A18%29\" = \"1%2F54\".\r\n" );
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document.write( "This is rate of work of one child.\r\n" );
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document.write( "So, 18 children will complete  \"1%2F3\"  of the job in one day, and\r\n" );
document.write( "it will take 3 days for them to complete the job.\r\n" );
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document.write( "Answer. 3 days.\r\n" );
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