document.write( "Question 89302: Solve the system by substitution. x + y = 12 y = 2x\r
\n" ); document.write( "\n" ); document.write( "Solve the system by addition or substitution. 3x – 4y = 8 6x – 2y = 10
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #64879 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"Solve the system by substitution. x + y = 12 y = 2x\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+%2B+y+=+12\"\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+highlight%282x%29+=+12\" Plug in y=2x (ie replace y with 2x)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3x=12\" Combine like terms\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x=4\" Divide both sides by 3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4+%2B+y+=+12\" Plug in x=4\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y+=+8\" Subtract 4 from both sides\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So our answer is (4,8)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "----------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "\"Solve the system by addition or substitution. 3x – 4y = 8 6x – 2y = 10\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: Solving a linear system of equations by subsitution

\n" ); document.write( "
\n" ); document.write( " Lets start with the given system of linear equations
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax-4%2Ay=8\"
\n" ); document.write( " \"6%2Ax-2%2Ay=10\"
\n" ); document.write( "
\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
\n" ); document.write( "
\n" ); document.write( " Solve for y for the first equation
\n" ); document.write( "
\n" ); document.write( " \"-4%2Ay=8-3%2Ax\"Subtract \"3%2Ax\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"y=%288-3%2Ax%29%2F-4\" Divide both sides by -4.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Which breaks down and reduces to
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=-2%2B%283%2F4%29%2Ax\" Now we've fully isolated y
\n" ); document.write( "
\n" ); document.write( " Since y equals \"-2%2B%283%2F4%29%2Ax\" we can substitute the expression \"-2%2B%283%2F4%29%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"6%2Ax%2B-2%2Ahighlight%28%28-2%2B%283%2F4%29%2Ax%29%29=10\" Replace y with \"-2%2B%283%2F4%29%2Ax\". Since this eliminates y, we can now solve for x.
\n" ); document.write( "
\n" ); document.write( " \"6%2Ax-2%2A%28-2%29-2%283%2F4%29x=10\" Distribute -2 to \"-2%2B%283%2F4%29%2Ax\"
\n" ); document.write( "
\n" ); document.write( " \"6%2Ax%2B4-%286%2F4%29%2Ax=10\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"6%2Ax%2B4-%283%2F2%29%2Ax=10\" Reduce any fractions
\n" ); document.write( "
\n" ); document.write( " \"6%2Ax-%283%2F2%29%2Ax=10-4\" Subtract \"4\" from both sides
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"6%2Ax-%283%2F2%29%2Ax=6\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"%2812%2F2%29%2Ax-%283%2F2%29x=6\" Make 6 into a fraction with a denominator of 2
\n" ); document.write( "
\n" ); document.write( " \"%289%2F2%29%2Ax=6\" Now combine the terms on the left side.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"cross%28%282%2F9%29%289%2F2%29%29x=%286%2F1%29%282%2F9%29\" Multiply both sides by \"2%2F9\". This will cancel out \"9%2F2\" and isolate x
\n" ); document.write( "
\n" ); document.write( " So when we multiply \"6%2F1\" and \"2%2F9\" (and simplify) we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"x=4%2F3\" <---------------------------------One answer
\n" ); document.write( "
\n" ); document.write( " Now that we know that \"x=4%2F3\", lets substitute that in for x to solve for y
\n" ); document.write( "
\n" ); document.write( " \"6%284%2F3%29-2%2Ay=10\" Plug in \"x=4%2F3\" into the 2nd equation
\n" ); document.write( "
\n" ); document.write( " \"8-2%2Ay=10\" Multiply
\n" ); document.write( "
\n" ); document.write( " \"-2%2Ay=10-8\"Subtract \"8\" from both sides
\n" ); document.write( "
\n" ); document.write( " \"-2%2Ay=2\" Combine the terms on the right side
\n" ); document.write( "
\n" ); document.write( " \"cross%28%281%2F-2%29%28-2%29%29%2Ay=%282%2F1%29%281%2F-2%29\" Multiply both sides by \"1%2F-2\". This will cancel out -2 on the left side.
\n" ); document.write( "
\n" ); document.write( " \"y=2%2F-2\" Multiply the terms on the right side
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=-1\" Reduce
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So this is the other answer
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"y=-1\"<---------------------------------Other answer
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So our solution is
\n" ); document.write( "
\n" ); document.write( " \"x=4%2F3\" and \"y=-1\"
\n" ); document.write( "
\n" ); document.write( " which can also look like
\n" ); document.write( "
\n" ); document.write( " (\"4%2F3\",\"-1\")
\n" ); document.write( "
\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax-4%2Ay=8\"
\n" ); document.write( " \"6%2Ax-2%2Ay=10\"
\n" ); document.write( "
\n" ); document.write( " we get
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " graph of \"3%2Ax-4%2Ay=8\" (red) and \"6%2Ax-2%2Ay=10\" (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " and we can see that the two equations intersect at (\"4%2F3\",\"-1\"). This verifies our answer.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " -----------------------------------------------------------------------------------------------
\n" ); document.write( " Check:
\n" ); document.write( "
\n" ); document.write( " Plug in (\"4%2F3\",\"-1\") into the system of equations
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Let \"x=4%2F3\" and \"y=-1\". Now plug those values into the equation \"3%2Ax-4%2Ay=8\"
\n" ); document.write( "
\n" ); document.write( " \"3%2A%284%2F3%29-4%2A%28-1%29=8\" Plug in \"x=4%2F3\" and \"y=-1\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"12%2F3%2B4=8\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"24%2F3=8\" Add
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"8=8\" Reduce. Since this equation is true the solution works.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So the solution (\"4%2F3\",\"-1\") satisfies \"3%2Ax-4%2Ay=8\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Let \"x=4%2F3\" and \"y=-1\". Now plug those values into the equation \"6%2Ax-2%2Ay=10\"
\n" ); document.write( "
\n" ); document.write( " \"6%2A%284%2F3%29-2%2A%28-1%29=10\" Plug in \"x=4%2F3\" and \"y=-1\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"24%2F3%2B2=10\" Multiply
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"30%2F3=10\" Add
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"10=10\" Reduce. Since this equation is true the solution works.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " So the solution (\"4%2F3\",\"-1\") satisfies \"6%2Ax-2%2Ay=10\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Since the solution (\"4%2F3\",\"-1\") satisfies the system of equations
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " \"3%2Ax-4%2Ay=8\"
\n" ); document.write( " \"6%2Ax-2%2Ay=10\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " this verifies our answer.
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );