document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034171>Question 1034171</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 2 inches more than twice its width,and its perimeter is 60 inches. find the length and width of the retangle\r<BR>\n" );
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document.write( "if w= the width of the rectangle, then the length equals_______ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648769 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648769\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter P = 60 = 2L + 2W<BR>\n" );
document.write( "We can also write<BR>\n" );
document.write( "L = 2W + 2<BR>\n" );
document.write( "Now plug that in to the above and get<BR>\n" );
document.write( "60 = 2(2W + 2) + 2W<BR>\n" );
document.write( "60 = 4W + 4 + 2W<BR>\n" );
document.write( "6W + 4 = 60<BR>\n" );
document.write( "6W = 56<BR>\n" );
document.write( "W = 56/6 = 28/3 inches<BR>\n" );
document.write( "so that<BR>\n" );
document.write( "L = 2(28/3) + 2 = 62/3 inches </SPAN>\n" );
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