document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1034080>Question 1034080</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A photo measures 8 in. by 10 in.Earl put it in a frame that added 2 inches to every side, Find the perimeter and total area for the photograph and frame.\r<BR>\n" );
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document.write( "Can I just change the size to 10 in. by 12 in. Would it be 44 in perimeter and 120 in area?\r<BR>\n" );
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document.write( "My book says the answer is P=52 in. and A=168 in Squared. What am I doing wrong? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #648701 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel555><B>jorel555(1290)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel555><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=648701\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have to add two inches to EVERY side, thus an 8 X 10 photo adds 4 inches EACH to the length and width.  So the new dimensions are 12 X 14, not 10 X 12---giving in a perimeter of 52 inches, and an area of 168 sq. inches!!!! </SPAN>\n" );
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