document.write( "Question 1032053: Represented by 3 consecutive odd integers, such that the product of the first and third was equal to 4 less than 5 times the second. \n" ); document.write( "

Algebra.Com's Answer #648676 by jorel555(1290) $\"\"$ $\"About$

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Let x be your first odd integer; then the second and third ones are x+2 and x+4, respectively:
\n" ); document.write( "x(x+4)=5(x+2)-4
\n" ); document.write( "x^2+4x=5x+6
\n" ); document.write( "x^2-x-6=0
\n" ); document.write( "(x-3)(x+2)=0
\n" ); document.write( "x=3,-2
\n" ); document.write( "The integers are 3,5, and 7!!!!!!! \n" ); document.write( "

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